CARA MENCARI INVERS DENGAN SKIL YANG SIMPEL
MENGGUNAKAN PYTHON 3.0
Mari kita lihat bagaimana pengerjaan Invers dengan menggunakan Python 3.0
import os
print(">>>>>>>RAHMAT HIDAYAT<<<<<<<")
print("<<<<<<SISTEM INFORMASI>>>>>>")
print(">>>>>>====04218007====<<<<<<")
a=1
while a==1:
print("=====Cara Pencari Invers Matriks=====")
a=int(input("Masukkan Nilai A = "))
b=int(input("Masukkan Nilai B = "))
c=int(input("Masukkan Nilai C = "))
d=int(input("Masukkan Nilai D = "))
e=int(input("Masukkan Nilai E = "))
f=int(input("Masukkan Nilai F = "))
g=int(input("Masukkan Nilai G = "))
h=int(input("Masukkan Nilai H = "))
i=int(input("Masukkan Nilai I = "))
#Cara Determinan
detA=(a*e*i)+(b*f*g)+(c*d*h)-(g*e*c)-(h*f*a)-(i*d*b)
print("\n=====CARA MATRIKS A=====")
print("|`",a," ",b," ",c,"`|")
print("| ",d," ",e," ",f," | ===> DetA = ",detA)
print("|_",g," ",h," ",i,"_|")
print("===============================")
#Cara Adjoin
a11=(e*i)-(h*f)
a12=(d*i)-(g*f)
a13=(d*h)-(g*e)
a21=(b*i)-(h*c)
a22=(a*i)-(g*c)
a23=(a*h)-(g*b)
a31=(b*f)-(e*c)
a32=(a*f)-(d*c)
a33=(a*e)-(d*b)
print('=====CARA ADJOIN======')
print("A11 = (+)| ",e,"",f," |=",a11," A12 = (-)| ",d,"",f," |=",a12," A13 = (+)| ",d,"",e," |=",a13)
print(" | ",h,"",i," | | ",g,"",i," | | ",g,"",h," |")
print("\nA21 = (-)| ",b,"",c," |=",a21," A22 = (+)| ",a,"",c," |=",a22," A23 = (-)| ",a,"",b," |=",a23)
print(" | ",h,"",i," | | ",g,"",i," | | ",g,"",h," |")
print("\nA31 = (+)| ",b,"",c," |=",a31," A32 = (-)| ",a,"",c," |=",a32," A33 = (+)| ",a,"",b," |=",a33)
print(" | ",e,"",f," | | ",d,"",f," | | ",d,"",e," |")
#printAdjoin
print("==============================================================================")
print("Adj = | ",a11*(1),"",a12*(-1),"",a13*(1)," |")
print(" | ",a21*(-1),"",a22*(1),"",a23*(-1)," |")
print(" | ",a31*(1),"",a32*(-1),"",a33*(1)," |")
print("")
print("Adjoin di Transpose menjadi = ")
print("A Traspose = | ",a11*(1),'',a21*(-1),'',a31*(1),' |')
print(' | ',a12*(-1),'',a22*(1),'',a32*(-1),' |')
print(' | ',a13*(1),'',a23*(-1),'',a33*(1),' |')
print("==============================================================================")
#Cara Invers
ina11=(1/detA*(a11*(1)))
ina12=(1/detA*(a12*(-1)))
ina13=(1/detA*(a13*(1)))
ina21=(1/detA*(a21*(-1)))
ina22=(1/detA*(a22*(1)))
ina23=(1/detA*(a23*(-1)))
ina31=(1/detA*(a31*(1)))
ina32=(1/detA*(a32*(-1)))
ina33=(1/detA*(a33*(1)))
print("\nA-1 = 1/Det A x Adj A")
print(' = 1/',detA,"| ",a11,'',a21,'',a31," |")
print(' | ',a12,'',a22,'',a32,' |')
print(' | ',a13,'',a23,'',a33,' |')
print('\n = | ',ina11,'',ina21,'',ina31,' |')
print(' | ',ina12,'',ina22,'',ina32,' |')
print(' | ',ina13,'',ina23,'',ina33,' |')
input("\nPress Enter to Continue!")
os.system('cls')
